Friday, August 1, 2008
Solucion 1.2
El campo magnético
B
: B(t=0)=2 ; B(t=sqrt(3))=0
=> B(t)=2-2t/sqrt(3)
Φ = B(t)*A*cos30 = sqrt(3) - t
ε = -dΦ/dt =>
ε = 1
VOLVER AL PROBLEMA
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